You really should learn to type a statement so it says what you mean. A math statement must have exactly one way to interpret it.
cos^2 * 6x is meaningless.
Making assumptions about where parentheses should be,
2cos^2(6x) - 1 = 0
cos^2(6x) = 1/2
cos(6x) = 1/â2
6x = pi/4 + 2npi or 6x = 7pi/4 + 2npi for all integers, n
x = pi/24 + npi/3 or x = 7pi/24 + npi/3 for all integer, n
Let 6x = t
2 * cos(6x)^2 - 1 = 0
2 * cos(t)^2 - 1 = 0
2 * cos(t)^2 = 1
cos(t)^2 = 1/2
cos(t) = -sqrt(2)/2 , sqrt(2)/2
t = pi/4 , 3pi/4 , 5pi/4 , 7pi/4 , 9pi/4 , ...
t = pi/4 + (pi/2) * k
k is an integer
6x = (pi/4) * (1 + 2k)
x = (pi/24) * (1 + 2k)
There you go.
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Answers & Comments
Verified answer
You really should learn to type a statement so it says what you mean. A math statement must have exactly one way to interpret it.
cos^2 * 6x is meaningless.
Making assumptions about where parentheses should be,
2cos^2(6x) - 1 = 0
cos^2(6x) = 1/2
cos(6x) = 1/â2
6x = pi/4 + 2npi or 6x = 7pi/4 + 2npi for all integers, n
x = pi/24 + npi/3 or x = 7pi/24 + npi/3 for all integer, n
Let 6x = t
2 * cos(6x)^2 - 1 = 0
2 * cos(t)^2 - 1 = 0
2 * cos(t)^2 = 1
cos(t)^2 = 1/2
cos(t) = -sqrt(2)/2 , sqrt(2)/2
t = pi/4 , 3pi/4 , 5pi/4 , 7pi/4 , 9pi/4 , ...
t = pi/4 + (pi/2) * k
k is an integer
6x = (pi/4) * (1 + 2k)
x = (pi/24) * (1 + 2k)
There you go.