This question is actually rather nice since your instructor has basically already given you one of the variables. Let's first look at -2z = -6
In order to solve this we simply need to divide both sides of this by -2 to give you
z = 3
Now let's focus on doing some elimination with the two equations:
Equation 1: 2x + 3y - z = -2
Equation 2: x + 2y + 3z = 9
Notice that we can easily use the elimination method on the 2x and x by simply multiplying Equation 2 by -2.
-2(x + 2y + 3z = 9)
-2x -4y - 6z = -18
Now let's add Equation 1 and Equation 2 together
2x + 3y - z = -2
-2x -4y -6z = -18
______________
-y -7z = -20
(This happened because the 2x and -2x canceled each other out.)
Now we learned at the start that z = 3, right? Now we simply plug it into the equation with two variables.
-y -7(3)= -20
-y -21 = -20
Now we simply add 21 to both sides
-y = 1
Then divide by a negative 1 to get our y positive and:
y= -1
Now that we believe y = -1 and z = 3, we now simply need to plug them back into Equation 1 or Equation 2. I'll do equation 1.
2x + 3(-1) -3 = -2
2x -6 = -2
Now we'll simply add 6 to both sides to get
2x= 4
Then divide by 2 to get
x = 2
So, to satisfy all three equations, I believe x = 2, y= -1, z = 3. Make sure to check these numbers and see that they work with ALL THREE equations. Everyone makes mistakes including myself, so always check the numbers yourself.
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Verified answer
-2z = -6
2x + 3y - z = -2
x + 2y + 3z = 9
z = 3
2x + 3y = 1
2x + 4y = 0
y = -1
x = 2
This question is actually rather nice since your instructor has basically already given you one of the variables. Let's first look at -2z = -6
In order to solve this we simply need to divide both sides of this by -2 to give you
z = 3
Now let's focus on doing some elimination with the two equations:
Equation 1: 2x + 3y - z = -2
Equation 2: x + 2y + 3z = 9
Notice that we can easily use the elimination method on the 2x and x by simply multiplying Equation 2 by -2.
-2(x + 2y + 3z = 9)
-2x -4y - 6z = -18
Now let's add Equation 1 and Equation 2 together
2x + 3y - z = -2
-2x -4y -6z = -18
______________
-y -7z = -20
(This happened because the 2x and -2x canceled each other out.)
Now we learned at the start that z = 3, right? Now we simply plug it into the equation with two variables.
-y -7(3)= -20
-y -21 = -20
Now we simply add 21 to both sides
-y = 1
Then divide by a negative 1 to get our y positive and:
y= -1
Now that we believe y = -1 and z = 3, we now simply need to plug them back into Equation 1 or Equation 2. I'll do equation 1.
2x + 3(-1) -3 = -2
2x -6 = -2
Now we'll simply add 6 to both sides to get
2x= 4
Then divide by 2 to get
x = 2
So, to satisfy all three equations, I believe x = 2, y= -1, z = 3. Make sure to check these numbers and see that they work with ALL THREE equations. Everyone makes mistakes including myself, so always check the numbers yourself.
-2z=-6 ......(1)
2x + 3y - z = -2........(2)
x + 2y + 3z = 9.........(3)
from equation (1)
-2z=-6
=> z = -6/(-2) = 3
put z = 3 into equation (2) and (3) to get equation (4) and (5)
2x + 3y - 3 = -2 ....... (4)
x + 2y + 3(3) = 9......(5)
simplify equa (4) and (5) to get equa (6) and (7)
2x + 3y = 1.......(6)
x + 2y = 0 .......(7)
from equa (7) make x the subject of the formula to get equa (8)
x = -2y.... (8)
put (8) into (6) to get
-2(2y) + 3y = 1
==> -4y + 3y = 1
==> y = -1
put y into equa (8) to get x
==> x = -2(-1)
==> x = 2
your final answer should be x = 2, y = -1, and z = 3
hope this help
now your turn ma 10 point haha
-2z = -6 or z= 3
so 2x+ 3y - z= -2 or 2x + 3y- 3 = -2 or 2x+ 3y = 1----------------------(I)
and x+ 2y + 3z = 9 or x+ 2y+ 9 = 9 or x+ 2y = 0 -------------(II)
from (I) & (II)
- y= 1 or y = -1
so x= 2
z= 3