Verified answer

Some of the Rules of indices:

X^m*X^n=X^(m+n)

X^m/X^n=X^(m-n)

(X^m)^n=x^(mn)

X^0=1

so

(4^3/2)^1/3 = 4^[(3/2)*(1/3)]

=4^3/6 = 4^1/2 = √4 =2

hope this helps

good luck

Well first consider the 4^3/2, this is the same as (4^1/2)^3=2^3=8 but our question is (4^3/2)^1/3 but we know 4^3/2 is 8 so (4^3/2)^1/3 = 8^1/3= 2

%Note that ^1/2 is the square root and ^1/3 is the cube root,

enjoy

Use the rules: (a^m)^n = a^m*n

So (3/2)*(1/3) = 3/6

4^3/6 = 4^1/2

Hope this helps

(4^3/2)^1/3= 4^1/2 = sqrt4 =2