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4y³ - 2y² --- This is not a trinomial expression but a binomial. To factorise it simply involves finding the common factor existing between 4y³ & - 2y² by H.C.F calculation, and that is 2y².

=> Factor out 2y², and you'll have

2y²(2y - 1).

Hence 4y³ - 2y² has been fully factorised as 2y²(2y - 1) ...Ans.

That is not a trinomial, but it can be factored. The first step in factorization is to see if there is anything that divides all of the terms. In this case, that turns out to be the only step.

4y³ - 2y² = 2y²(2y - 1)

2y^2(2y-1)

you will just get their common factor.

2y^2 is the common factor because if you will divide 4y^3 to 2y^2 the answer is 2y

and if you will divide 2y^2 by negative 2y^2 the answer is negative one

this is binomial

4y^3 - 2y^2

factor out 2y^2

=2y^2(2y-1)

To fator jus put 2y^2 in evidence... it is 2y^2 ( 2y -1) OK!

To confirm just multiply and get 4y^3 - 2y^2 OK!

4y³ - 2y²

first look for common factors. 4y³ = 2²y³, so 2y² is the greatest common factor.

4y³ - 2y² = 2y²(2y - 1)

4y^3-2y^2,

2y^2(2y-1).

Answer: 2y^2(2y-1).

Give me best answer.

get what is common

(4)(y)(y)(y)-(2)(y)(y)

(2y^2)(2y-1)