I need some help in figuring out how to do this word problem about multiplying polynomials: One side of a square is increased by 1 cm, and an adjacent side is decreased by 3 cm. The area of the resulting rectangle is 21cm^2 less than that of the square. Find the dimensions of the square. Thanks for your help!
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The original figure was a square with equal sizes to each side, by definition... call each original side's length "x" ... the area of the original square was x*x.
x*x - 21 = the area of the new rectangle
(x+1)*(x-3) = the area of the new rectangle also
thus:
x*x - 21 = (x+1)*(x-3)
x*x - 21 = x*x - 3x + x - 3
3x - x = 18
2x = 18
x = 9
The area of the original square was 9*9 = 81 square centimeters
The area of the new rectangle is (9+1) * (9-3) = 10 * 6 = 60 cm^2
The difference between the areas is 81 - 60 = 21 centimeters squared, as required.
Let s = length of a side of a square
Let L_Rectangle = length of the new rectangle
Let W_Rectangle = width of the new rectangle
If you are having trouble translating words into expressions, break up what you're given into smaller pieces first.
Given: one side of a square
Means: s
Given: is increased by 1 cm
Means: + 1
Put them back together.
Given: One side of a square is increased by 1 cm
Means: L_Rectangle = s + 1
Given: An adjacent side
Implied: You remember that a square's sides are all the same length
Means: s
Given: is decreased by 3 cm
Means: - 3
Put them back together.
Given: An adjacent side is decreased by 3 cm.
Means: W_Rectangle = s - 3
Given: The area of the resulting rectangle
Implied: You know the area formula for a rectangle: A = L * W
Means: Area_Rectangle = L_Rectangle * W_Rectangle
Given: is 21 cm^2 less than
Means: -21 +
Given: that of the square
Implied: You know the area formula for a square: A = s^2
Means: s^2
Put them back together.
Given: The area of the resulting rectangle is 21cm^2 less than that of the square.
Means: L_Rectangle * W_Rectangle = s^2 - 21
Your system of 3 equations is:
L_Rectangle = s + 1
W_Rectangle = s - 3
L_Rectangle * W_Rectangle = s^2 - 21
Substitute L_Rectangle with s + 1 in the third equation.
L_Rectangle * W_Rectangle = s^2 - 21
(s + 1) * W_Rectangle = s^2 - 21
Substitute W_Rectangle with s - 3.
(s + 1) * (s - 3) = s^2 - 21
(s + 1)(s - 3) = s^2 - 21
Expand.
s(s) + s(-3) + 1(s) + 1(-3) = s^2 - 21
s^2 - 3s + s - 3 = s^2 - 21
s^2 - 2s - 3 = s^2 - 21
Subtract s^2 from both sides.
s^2 - 2s - 3 - s^2 = s^2 - 21 - s^2
-2s - 3 = -21
Add 3 to both sides.
-2s - 3 + 3 = -21 + 3
-2s = -18
Divide both sides by -2.
-2s / -2 = -18 / -2
s = 9
ANSWER: The square's sides are 9 cm each.
CHECK:
L_Rectangle = s + 1
L_Rectangle = 9 + 1
L_Rectangle = 10
W_Rectangle = s - 3
W_Rectangle = 9 - 3
W_Rectangle = 6
L_Rectangle * W_Rectangle = s^2 - 21
10 * 6 = 9^2 - 21?
60 = 81 - 21?
60 = 60?
TRUE
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