Verified answer

✐Derivation✐

Substitute the point to the equation to determine if it works or not!

-4(1) + 2(6) = 8

-4 + 12 = 8

8 = 8

Yes, that point works!

So to see whether this point is on the line you simply have to plug in the x-coordinate and solve for y. If y is equal to six in this case, then you know that this point is on the line.

So:

-4(1) + 2y = 8

-4 - 8 = -2y

-12 = -2y

-12/-2 = -2/-2 (y)

6 = y

Therefore because y=6, you know this point is on the line! :)

Plug in the given point (1,6) into the equation and see if it satisfies the equation.

-4(1) + 2(6) = -4 + 12 = 8

Thus, it satisfies the equation. The point is on the line.

Simply substitute the value of x and y in the equation and check if LHS = RHS

Given equation: -4x+2y = 8

Check if the point whose coordinate(1,6) lies on the line.

-4x+2y = 8

LHS: -4x+2y = -4*(1) + 2(6) = -4 + 12 = 8

So, as you can see LHS = RHS which means the point is on the line.

Plug 1 in for x, and 6 in for y. If the result is true, then the point is in the line.