Verified answer

y ≤ 4 - 1

-2x + 3y < -6

y ≤ 3 and -2x + 3y < -6

Since 3y does not contain the variable to solve for, move it to the right side of the inequality by subtracting 3y from both sides:

y ≤ 3 and - 2x< -3y - 6

Divide each term in the inequality by - 2:

y ≤ 3 and x > (3y/2) + 3

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5x+3y > -6

2y+x < 6

5x > -3y-6 and 2y+x < 6

x > -(3(y+2))/5 and 2y+x<6

x > -(3(y+2))/5 and x < -2y+6

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2x-3y ≥ 9

-x-4y ≥ 8

2x ≥ 3y+9 and -x-4y ≥ 8

x ≥ (3(y+3))/2 and -x-4y ≥ 8

x ≥ (3(y+3))/2 and -x ≥ 4y+8

x ≥ (3(y+3))/2 and x ≤ 4y*-1+8*-1

x ≥ (3(y+3))/2 and x ≤ -4y - 8