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1)n=19. Since you are adding by zero, the number is the same. 19+0=19

2)n=22. Divide 22 by 1. You will get 22.

3)n=0. Anything multiplied by 0 will give you zero.

4)n=22. This is the same type of problem as number 1. Anything added by zero gives you the same number.

5)n=4. Divide 1 by 1/4 to get 4. You can also multiply 4 times 1/4 to cancel the denominator and just get 1.

6)n=1. Anything multiplied by 1 gives you the same number.

7)n=0. Anything added by zero gives you the same number. You will subtract 5 from both sides to get: 0=n

8)Simplify the right side to get: 2 x n=6. Divide 6 by 2. n=3

9)Do distributive property on the left side: 2(9) - 2(3)= 2n. Simplify to: 18-6=2n.

12=2n. Divide both sides by 2. n=6

10)Because of PEMDAS, do what is inside the parentheses first.

21+4 = n+4. Simplify to: 25 = n+4. Subtract 4 from both sides.

n=21.

11)Simplify the left side: 9= n + 4. Subtract 4 from both sides. n=5.

12)n=0. Anything multiplied by 0 gives you zero.

13)Divide both sides by 3 to get: n=1/3

14)Because of PEMDAS, do what is in parentheses first.

11- (18/2) = 11-n

11- 9 =11 - n

n=9. The equation on the left already has 11, so you can tell directly that the second number must be the same one on the left (9)

15)Because of order of operations, do the 4^2 first, which equals 16.

7(16/16)

7(1)= 7.

16)Do what is in parentheses first: 2(5-5).

2(0)= 0.

17)Do what is in parentheses first. 4-3 (7-6). Simplify: 1(1)= 1

18)Do what is in parentheses first: 4(8-8) + 1=

4(0) + 1. Work from left to right. Because of PEMDAS, multiplication is done first: 0+1= 1

19)Do what is in parentheses first because of PEMDAS: 6+9 [10-2(5)]

Simplify: 15(10-10)=

15(0)= 0

20)Do the 3-1 first: 2(6/2) x 1/2. Because of order of operations, work from left to right by carrying out each multiplication.

6 x 1/2 = 3

Hope this helps:)

1) n + 0 = 19, so n = 19 - 0 = 19

2) 1 * n = 22, so n = 22

3) 28 * n = 0, so n = 0/28 = 0

4) 0 + n = 22, so n = 22

5) 1/4 * n = 1, so n = 1 / (1/4) = 1 * 4 = 4

6) n * 9 = 9, so n = 9 / 9 = 1

7) 5 = n + 5, so n = 5 - 5 = 0

8) 2 * n = 2 * 3 so n = (2*3)/2 = 3

9) 2(9 - 3) = 2 (n), so n = (9 - 3) = 6

10) (7 * 3) + 4 = n + 4, so n = (7 * 3) = 21

11) 5 + 4 = n + 4, so tak 4 from both sides, 5 + 4 - 4 = n + 4 - 4, n = 5

12) n = 14 * 0 = 0

13) 3n = 1, n = 1/3

14) 11 - (18/2) = 11 - n, n = (18 / 2) = 9

15) 7(16/4^2) = 7

16) 2(5 - (15 / 3)), 2(5 - 5) = 0

17) 4 - 3(7 - (2 * 3)), 4 - 3(7 - 6) = 4 - 3(1) = 1

18) 4(8 - (4 * 2)) + 1, 4(8 - (8) + 1 = 1

19) 6 + 9(10 - 2(2 + 3)), 6 + 9(10 - 2(5)) = 6 + 9(10 - 10) = 6

20) 2(3 / 3 - 1) * 1/2, the half and he 2 cancel leaving, 3/3-1 = 0

A.) an entire of 456 tickets have been bought, so a + s = 456. the quantity of money produced from each style of cost ticket is its cost more advantageous by employing how many have been bought. consequently, the quantity of money produced from the person tickets on my own is $3.50 * a = 3.5a money. Likewise, the quantity of money produced from the pupil tickets on my own is $a million * s = s money. the full cost ticket revenues equals $1131, so 3.5a + s = 1131. for this reason, your device of equations is: a + s = 456 3.5a + s = 1131 B.) Multiply the 1st equation by employing -a million so it extremely is -a - s = -456. Now upload this equation to the 2d equation to sparkling up for a with the aid of removing s from the ensuing equation: (3.5a + s = 1131) + (-a - s = -456) = (2.5a = 675) 2.5a = 675 (divide the two aspects by employing 2.5) a = 270 And you are able to now sparkling up for s. a + s = 456 (replace 270 for a) 270 + s = 456 (subtract 270 from the two aspects) s = 186 answer: 270 person tickets and 186 pupil tickets