Verified answer

Notice that each term is 8 plus the previous term, and so by definition the sequence is arithmetic (as the difference between any two consecutive terms of the sequence is the same).

This difference is the common difference, so the common difference is 8. Adding 8 to 31 yields the next term of the sequence to be 39. Adding 8 and 16 to 39 yields the second and third term after 31 to be 47 and 55 respectively.

Yes its in arithmetic sequence.

Common difference is 15-7=8

or 23-15=8. so on

next 3 terms are.... 31+8=39, 39+8= 45, 45+8= 53.

enable the unique sequence 3 numbers are a, a + 3, and a + 6. If the 1st style is greater desirable by making use of a million, the 2nd greater desirable by making use of 6 , and the 0.33 by making use of 19 So, the geometric sequence 3 numbers are a + a million, a + 9, and a + 25. Above numbers following geometric sequence so, t? / t? = t? / t? (a + 9)/(a + a million) = (a + 25)/(a + 9) bypass multiplication. (a + 9)(a + 9) = (a + 25)(a + a million) FOIL approach: the manufactured from 2 binomials is the sum of the products of the 1st words, the Outer words, the interior words and the final words. a2 + 9a + 9a + 80 one = a2 + 1a + 25a + 25 a2 + 18a + 80 one = a2 + 26a + 25 Subtract a2 from the two aspects. 18a + 80 one = 26a + 25. Subtract 18a from the two aspects. 80 one = 8a + 25 Subtract 25 from the two aspects. 8a = fifty six Divide the two aspects by making use of 8. a = 7. hence the unique sequence is 7, 10, 13. The geometric sequence is 8, sixteen, 32.