Algebra Coin Problem with variables?
Word Problem:
You have $10.58 in pennies and quarters. The total number of coins is 74. How many quarters do you have?
Can someone please show me the equation and the steps to solve the problem? Thank you!
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Verified answer
Let x = # of quarters
Let 74-x = # of pennies
.25*(x)+.01*(74-x)=10.58
.25x+.74-.01x=10.58
.24x+.74=10.58
Subtract .74 from both sides
.24x=9.84
Divide both sides by .24
x=41
Answer: 41 Quarters