Verified answer

If i were you, i would square the whole thing so it reads, 64-(-81/2) -> 128/2+81/2 -> 209/2

:)

Parenthesis would help. Are you dividing by two then taking the square root, or is it the other way around? I'll assume the first. If it's the second, you can easily figure it out.

The square root of -81 is the same as the square root of -1 times the square root of 81. This is i*the square root of 81. So, writing it in standard from (a+bi), we get

8-1/2*(the square root of 81)i

This is taken from quadratic formula correct?

so the correct way to write it would be (8-√-81) / 2

so, although technically you cant square -81, using complex numbers youd get the square root 81 x -1. the square root of -1 is known as i, so you can rewrite it as 9√-1 or 9i. That leave (8 - 9i) /2 which simplifyes as:

4 - (9i/2)

a million) x^2 + 4x + 5 = 0 x = [-b ±?(b^2 - 4ac)]/2a a = a million b = 4 c = 5 x = [-4 ±?(sixteen - 20)]/2 x = [-4 ±?-4]/2 (imaginary huge form) (no actual roots) = = = = = = = = 2) x^2 + 5x + 4 = 0 x^2 + 4x + x + 4 = 0 (x^2 + 4x) + (x + 4) = 0 x(x + 4) + a million(x + 4) = 0 (x + 4)(x + a million) = 0 x + 4 = 0 x = -4 x + a million = 0 x = -a million ? x = -4 , -a million