Verified answer

What is the question? Assuming you want to solve for x

let z = x²

z² – 8z + 6 = 0

quadratic equation:

to solve ax² + bx + c = 0

x = [–b ±√(b²–4ac)] / 2a

z = [8 ±√(64–24)] / 2

z = [8 ±√40] / 2

z = [8 ± 2√10] / 2

z = 4 ± √10

now plug x back in

x² = 4+√10, 4–√10

x = ± √(4+√10), ± √(4–√10)

numerically that is

x = ±2.676, ±0.9153

check the answers by plugging them back in the original equation.

you can do that.

(x²)² - 8(x²) + 6 = 0

((x²) - 4)² - 10 = 0

((x²) - 4)² = 10

x² - 4 = ±√10

x² = 4 ± √10

x = ±√(4 ± √10)

x = √(4 - √10), √(4 + √10), -√(4 - √10), -√(4 + √10)

Hi Kay Kay

Have you tried using the quadratic formula? The equation can not be solved by simple factoring.

Hope this helps. Let me know if you need more help. I'm on YM or by email.

Best of luck.