Algebra Problems pleease?
I have 2 problems i got wrong on a test that need to be re-answered. Please help.
Determine whether the equation is a linear equation. If so, write the equation in standard form.
1) 8n-9m = 6-3m
a. yes; 6m-8n = -6
b. yes; 6m+8n = 6
c. yes; 8n-6m = -6
Find the solution set for the equation, given the replacement set.
y = 7x + 6; {(5, 41), (6, 44), (4, 39), (7,42)}
a.{(4, 39)}
b.{(6, 44)}
c.{(5, 41)}
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1. m and n are in degree of 1 so it's linear
add -3m on both sides will give you 8n - 6m = 6 which is the answer, if you multiply -1 on both sides, you will get answer (a)
2. simply subsitute x = 4,5,6 into the equation, you found that (c) is correct
you should have a set as
5-41, 6-48 4-34 7-55
For the 1st question: 10 = (-2/3) (4x + 5) 10 = (-8/3)x + (-10/3) 10 + (10/3) = (-8/3)x (30 + 10)/3 = (-8/3)x 40/3 = (-8/3)x (20/3) cases (-3/8) = x -5 = x by skill of Reflective supplies of equations: x = -5 ----- For the 2nd question: i visit coach here the step by skill of step skill of adjusting a Mathematical situation. representation: permit x be the shorter component of the rectangle. permit (6x - 3) be the longer component of the rectangle. Given: Perimeter of the Rectangle = 50 in Equation: considering that perimeter is comparable to 2 times the sum of the shorter component and the longer component, we've the equation: 2[x + (6x-3)] = 50 answer: 2[x + (6x-3)] = 50 2(7x - 3) = 50 14x - 6 = 50 14x = fifty six x = fifty six/14 x = 4 replace x interior the equation 6x - 3 to get the size of the longer component: length of the Longer component = 6x - 3 length of the Longer component = 6(4) - 3 length of the Longer component = 24 - 3 length of the Longer component = 21 answer: The length of the shorter and the longer sides of the rectangle is 4 in and 21 in, respectively.