Algebra: Recurring Sequence problem?
The first 4 numbers of the sequence are 100, 50, 25, 12.5
Find the possible common member in the analytical and recursive form.
My question is WHAT? I do internet school so I don't have a teacher I can just ask very quickly. I studied the chapter, but I don't get the whole idea of it at all.
PLEASE HELP!
Update:The answer in the back of the book is
recursive:
a = a
n n-1 divided by 2
n= 2,3,4 and a1 = 100
and analytical:
a = 100x(1/2)^n-1
n
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Verified answer
The first term is 100 times the ratio raised to n - 1 power. The first term
100*(1/2)^(1) = 50
100*(1/2)^(2) = 25
100*(1/2)^(3) = 12.5
n = 2
n = 3
n = 4
What an odd notation. I would just put 100*(1/2)^n for convience
it is in the form of Geometric Progression(G.P.).
it's common ration is 1/2
it's common member in in analytical and recursive form is
a (r)^(n-1)
where a is the first term(here 100) , r is the common ratio(here 1/2) and n is the number of the term
My best guessing is that their asking for your answer in words and in the form of a formula
Recursive:
A formula that generates the successive terms of a recursion.
analytical:
using or skilled in using analysis (i.e., separating a whole--intellectual or substantial--into its elemental parts or basic principles)
GOOD LUCK!
I hope I don't see this as a submitted document on the due date of Monday, April 8th.