Find x,y, and z:
x(x+y+z)=6
y(x+y+z)=12
z(x+y+z)=18
It's a one-liner:
By simple inspection : try x=1 , then (x+y+z)=6 ; y=2 and z=3
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Verified answer
It's a one-liner:
By simple inspection : try x=1 , then (x+y+z)=6 ; y=2 and z=3