Altere el flash 0 de mi psp y ahora no prende.Que puedo hacer para arreglarlo?!(10 puntos al que me resuelva)?
Estaba de lo mas entretenido modificando el flash 0 y le cambie las olas y puse una foto bitman 60x34 de 5.?? kb apague el psp saque la memoria y cuando prendi el psp se vio todo *****, solo prende la luz verde pero no hace mas nada.Mi psp esta en version 3.52 m33-4 y tiene recovery pero ni siquiera puedo entrar alli y no tengo el pandora para hacerle el recovery.Si alguien me ayuda le doy 10 puntos, mi amistad, mi disponibilidad y mil gracias.Si necesitas mas [email protected]
I really need it!!!
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Mi español no es intento tan bueno, (ni uno ni otro es mi inglés) solamente enfermo ayudar.
si usted lo gira y la luz verde se adelanta y da vuelta apagado después de algunos segundos, es bricked. si usted linado entra en modo de la recuperación, es bricked. si usted no tiene una batería del pandora, usted necesita conseguir uno allí es un nuevo método que el doesnt requiere un psp permitido los soportes lógico inalterable de encargo hacerlo, pero será una modificación dura permanente, así que no puede ser vuelto a una batería de trabajo.
http://www.pspmod.com/forums/hardware/24224-pandor...
in case you ever took precalculus or another math classification which covers residences of applications, you how you are able to nonetheless verify the area of the function. between the crimson flags to look out for is once you divide by potential of 0. on your expression, while x = 3, the denominator is 0. subsequently, the area is each and every quantity beside 3. regrettably, the quantity you attempt to plug in (x = 3) is the only quantity that would not paintings throughout this function. to verify this huge-unfold hand, you0 can graph this function on a TI-80 3. in case you zoom in close to the graph at x = 3, you will see that there is a sparkling spot there! that's by means of the fact, as suggested above, there merely isn't a value of the expression at x = 3. you are able to say, nicely it sounds as though like the respond could be 6, observing the graph. this theory of what the respond "could be" is what limits are all approximately. The values of the function on the left and top of x = 3 all bypass in direction of 6 as you catch up with and nearer. So we are saying the cut back as x is going to 3 is 6. So regardless of if it is not technically the respond, 6 is your terrific selection. 0 heavily isn't terrific suited in any sense. the very terrific answer is to declare that the expression is undefined at x = 3. This issue illustrates why 0/0 is named indeterminate. throughout this issue, 0/0 in a manner equals 6. the thought that 0/0 can equivalent something is actual the essence of calculus.