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i just did that question 4u. in ut other quest. again, if u don't understand ask me. feel free to.

2x- y= 9

2x -9 =y

substitute in the other equation

x+ 3 (2x-9) = 8

x + 6x -27= 8

7 x = 8 +27= 35

x=5

from first equation

y= 2x-9= 10-9=1

Let's check the result:

from second equation

5+ 3y= 8

3y= 8-5=3

y=1 solution checked

First you need to eliminate one of the unknowns; if you do y first you need to make the number of ys the same, so multiply the first equation by 3;

6x - 3y = 27

x + 3y = 8

then add the two together to eliminate the ys

7x = 35

therefore x = 5

to get the value of y just substitute in the value of x

10 - y = 9

5 + 3y = 8

therefore y = 1

1. Rearrange the equations so that you have one solved for x and one solved for y. You will have x=something and y=something.

2. Plug the expression for x into the y= equation to solve for y.

3. Plug the y value into the x= equation to find the point x.

4. You can check you answers by plugging both variables into the original equations. You should get some number=the same number.

Multiply all of the numbers in the second equation by -2 and add it to the first equation.

2x - y = 9

-2x - 6y = -16

___________

0 - 7y = -7

Any then solve for y, and then insert the value of y in either of the original problems and solve for x.

Download the program GraphCalc. Re-write the equation for Y= and plug the two equations into the program and find the intersection.

X=5; Y=1

Well not sure what you are solving for , maybe you want it in slope form.

2x - y = 9

-2x -2x (subtract x from left side bring to right)

-1y = -2x + 9 (divide -1 from each side)

-1 -1 -1

y = +2x -9 (answer) (2x would be your slope) (-9 would be y intercept)

Will do other problem now.

you can use two methods im going to just use the substitution method okay?:)

2x-y=9

-y=9-2x

(-1)-y=(-1)9-2x

y=-9+2x

x+3(-9+2x)=8

x-27+6x=8

x+6x=35

7x=35

x=35/7

x=5

(5)+3y=8

3y=3

y=1

hope this helps:)

x=5

y=1