¿ayuda con esta tarea de calculo!?
necesito que me solucionen estos problemas por favor pero con el prosedimiento!
factor comun:
14m2n+7mn:
4/35a b-12/5ab + 8/15a Ala 2 b ala 3 -16/25 a Ala 3 b:
2x a la 2+6x+8x a la 3-12x a la 4:
10p2q3 +14p3q2-18p4q3-16p5q4:
m a la 3 n a la2 p a la 4 + m ala 4 n a la 3 p ala 5- m a la 6 n a la 4 p a la 3 :
x a la 2(p+q) + y2(p+q):
5x(b2+1)+(x2+1)(b2+1):
a2+1-b(a2+1):
(x+1)(x-2)+3y(x-2):
(x+y)(n+1)-3(n+1):
gracias!
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Verified answer
14m²n+7mn = 7mn (m + 1)
(4/35)ab - (12/5)ab + (8/15)a²b³ - (16/25)a³b = (4/5)ab ( 1 - (3/7) + (2/3)ab² - (4/5)a²)
(4/5)ab ( 1 - (3/7) + (2/3)ab² - (4/5)a² ) = (4/5)ab ( - (4/5)a² + (2/3)ab² + (4/7) )
(4/5)ab ( - (4/5)a² + (2/3)ab² + (4/7) ) = (4/5)ab ( a( -(4/5)a + (2/3)b² ) + (4/7) )
2x² + 6x + 8x³ -12x^4 = 2x ( x + 3 + 4x² - 6x³) = 2x ( - 6x³ + 4x² + x + 3 )
2x ( - 6x³ + 4x² + x + 3 ) = 2x ( x( x(-6x + 4 ) + x + 3 )
10p²q³ + 14p³q² - 18p^4q³ - 16p^5q^4 = 2p²q² ( 5 + 7p - 9p²q - 8p³q² )
2p²q² ( 5 + 7p - 9p²q - 8p³q² ) = 2p²q² ( - 8p³q² - 9p²q + 7p + 5 )
2p²q² ( - 8p³q² - 9p²q + 7p + 5 ) = 2p²q² ( -p²q( p(8q + 9) + 7p + 5 )
2p²q² ( -p²q( p(8q + 9) + 7p + 5 ) = 2p²q² ( p( -pq( p(8q + 9) + 7) + 5 )
m³n²p^4 + m^4n³p^5 - m^6n^4p³ = m³n²p³ (p + mnp² - m³n²)
m³n²p³ (p + mnp² - m³n²) = m³n²p³ (p + mn(p² - m²n)
x^2(p+q) + y^2(p+q) = x^2(p+q) + y^2(p+q) <no se simplifica
5x(b2+1)+(x2+1)(b2+1) = (b² + 1)( 5x + x² + 1 )
(b² + 1)( 5x + x² + 1 ) = (b² + 1)( x² + 5x + 1 )
(b² + 1)( x² + 5x + 1 ) = (b² + 1)( x(x + 5) + 1 )
a² + 1 -b(a²+1) = a² + 1 -a²b + b
a² + 1 -a²b - b = a²(1 - b) + 1 - b
a²(1 - b) + (1 - b) = (1 - b)(a² + 1)
(x + 1)(x - 2) + 3y(x - 2) = (x - 2)( (x + 1) + 3y )
(x - 2)( (x + 1) + 3y ) = (x - 2)( x + 3y + 1 )
(x + y)(n + 1) - 3(n + 1) = (n + 1)( (x + y) - 3 )
(n + 1)( (x + y) - 3 ) = (n + 1)( x + y + 3 )