Bernoulli trials question?
Each year a company selects 5 employees for a management training program. On the average 40% of those sent finish in the top 10% of their class. If we consider an employee finishing in the 10% a success in a binomial experiment then for the 5 employees entering the program there exists a binomial experiement distribution involving P(x successes out of 5).
a)Write a function defining the distribution
b)Compute the mean and standard deviation
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sorry cant really help with (a) but i think it might be something like
X~Bin ( 5, 0.4)
as binomial distribution is represented by X~Bin( n ,p)
with n being the sample number and p as the "successes"
(b) with binomial distrubution to find mean it is simply n multiply with p
so 5x0.4
mean =2
and to find stadard deviation , we simply find the variance then square root it.variance is calculated by
np(1-p)
so 5x0.4(1-0.4)
=1.2
remeber that is the variace so we got to square root it to find standard deviation
=1.2 ^0.5
so standard deviation is 1.0954
hope this helps