por favor es urgente la respuesta
Masa molar NH3 = 14+1x3 = 17g/mol
densidad del agua = 1g/mL --> 70g = 70mL
Molaridad:
M = masa / (PM x V)
M = 30g / (17g/mol x 0.07L)
M = 25.21 mol/L o Molar
Normalidad:
N = f x M
f = 1 (amoniaco tiene la capacidad de captar un proton como base)
N = 1 x 25.21 Molar
N = 25.21 Normal
Fraccion molar
MM H2O = 1x2 + 16 = 18g/mol
mol = masa / PM = 70g / 18g/mol = 3.89 moles
moles totales = 25.21 mol + 3.89 mol = 29.1 mol
fraccion molar NH3 = 25.21 mol / 29.1 mol = 0.87
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Verified answer
Masa molar NH3 = 14+1x3 = 17g/mol
densidad del agua = 1g/mL --> 70g = 70mL
Molaridad:
M = masa / (PM x V)
M = 30g / (17g/mol x 0.07L)
M = 25.21 mol/L o Molar
Normalidad:
N = f x M
f = 1 (amoniaco tiene la capacidad de captar un proton como base)
N = 1 x 25.21 Molar
N = 25.21 Normal
Fraccion molar
MM H2O = 1x2 + 16 = 18g/mol
mol = masa / PM = 70g / 18g/mol = 3.89 moles
moles totales = 25.21 mol + 3.89 mol = 29.1 mol
fraccion molar NH3 = 25.21 mol / 29.1 mol = 0.87