what is the maximum height the hill could be to ensure the car does not stop (assume there is no friction) if the kinetic energy of the car and the rider comes to total 3070.62 joules??????
Using the formula GPE=mgh and KE=0.5mv^2, where GPE is gravitational potential energy, KE is kinetic energy, m is mass, g is acceleration due to gravity (10m/s), h is height and v is velocity.
Since the law of conservation of energy states that energy can neither be created nor lost and the total amount of energy remains constant, we can conclude that the kinetic energy is equal to the gravitational potential energy. As such, equate both equations, 0.5mv^2=mgh, sub in the values, manipulate and you should get h, the height.
So, 3070.62J=mgh. Since g=10, 307.062=mh. Now, this is where info is missing. Find the mass of the object and divide it such that h=307.062/m.
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Using the formula GPE=mgh and KE=0.5mv^2, where GPE is gravitational potential energy, KE is kinetic energy, m is mass, g is acceleration due to gravity (10m/s), h is height and v is velocity.
Since the law of conservation of energy states that energy can neither be created nor lost and the total amount of energy remains constant, we can conclude that the kinetic energy is equal to the gravitational potential energy. As such, equate both equations, 0.5mv^2=mgh, sub in the values, manipulate and you should get h, the height.
So, 3070.62J=mgh. Since g=10, 307.062=mh. Now, this is where info is missing. Find the mass of the object and divide it such that h=307.062/m.
mgh=1/2mv^2
2mgh=mv^2
2gh=v^2
h=v^2/2g but ther's no mass how can we get v?
whats the mass?