Verified answer

Use change of base:

log (base a) b = log (b) / log (a)

log (base 2) 10 x log (base 10) 2 = Log (base a) Y

log(10) / log(2) x log(2) /log(10) = Log (base a) Y

1 = Log (base a) Y

Y = a^1

Y = a

log (base 2) 10 x log (base 10) 2 = log (base a) y

log(base 2)10 x {[(log(base 2)2]/[log(base 2)10]} = log(base a)y

log (base 2) 2 = log (base a) y

1 = log (base a) y

y = a^1

y = a

log (2) 10 * log *(10) 2 = log (a) y

we'll convert everything to base a:

{ log(a) 10 / log(a) 2 } * {log(a) 2 / log(a) 10} = log(a) y

log(a) y = 1

y = a.

y = a