Verified answer

There is no reason you can't do this on your own. The formulas are simple and available everywhere including your text book.

a) 1/Ce = 1/C1 + 1/C2 + ... 1/Cn

b) The charge is the same on all capacitors, so calculate Q for Ce, then use Q for all others.

c) Q = CV and you know Q and C.

And don't use pd for potential difference since it is typically power drop.

d) see my answer on your question about parallel caps

e) learn to look up simple and general things like capacitor formulas

EDIT:

To the poser IEEE instructor, you're better off not playing with the big dogs, here.

Now, go teach yourself something about electroSTATIC charge:

http://www.wisc-online.com/objects/ViewObject.aspx...

One day, you playing doctor is going to get someone hurt with your ignorant advice.

a) 1/Ct =1/C1 +!/C2 + 1/C3 = 1?12+1/9+1/6 = 0.083+0.111+0.166 = 1/0.36 = 2.777 x 10-6 farads

As capacitor are in series the effective capacitance 2.777 x10-6 farads

b) Q = C x V = 2.777 x10-6 x 100v = 0.000277 coulombs ( capacitance Farads x volts )

c) no current flow as cacacitors are a current block to DC no Pd across capacitors except 100 v across the plte of the first and negitive plate of the last capacitor

d) Energy only stored in the effective capacitance 2.777 x 10-6 farads

capacitors in series are product over sum or 1/c1 + 1/c2 etc

with dc capacitors act as storage batteries

add

a capacitor will achieve 63% of its charge in 2.2 Tau (= 2.2CR)

a capacitor will be within 1% of its fully charged state in 5 time constants (5CR)

you also need to realise that ac, as opposed to dc, merely passes through a capacitor, and in the process causes a phase difference between the voltage and the current, (and as such they are resistive to the frequency of ac), which for basic evaluation is stated as the current leading the voltage by 90o, in reality this very rarely exceeds 84 degrees, and at the calculated value for RC networks (the -3dB point) is 45 degrees.

Hi in a nutshell a capacitor blocks d.c. volts so nothing flows at all.

so no total capacitance , no charge on any capacitors. and no energy stored.

in fact a useless exercise in series.