Verified answer

ok

as the points are on both line and the circle so

y=x+4

(x-6)^2+(x+4-3)^2=5^2

x^2-12x +36 + x^2 +2x+1 =25

2x^2 -11x +12 =0

(2x- 3 ) (x -4 ) = 0

x=3/2 or x=4

so y=5.5 or y=8

so p=(1.5,5.5) , q=(4,8)

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I don't know what do u want next?

(x-6)^2 + (y-3)^2 = 5^2;

since y=x,

(x-6)^2 + (x-3)^2 = 5^2

x^2-12x+36 + x^2-6x+9 = 25

2x^2 -18x +20 = 0

x^2 - 9x + 10 = 0

I don't get your answer

What is the equation of the line? y=x+ ????

y = x + ?