Jo's circular wheel needs to complete eight full rotations or 8x 360=2880 to roll 12 meters. How many degrees must the wheel rotate to roll .5 meters?
You know that it takes 2880 degrees of rotation to go 12 meters, so this is a simple ratio problem.
2880 / 12 = x / .5
2880 x .5 / 12 = x
x = 120 degrees
2880 to 12m
x to .5 m
so
2880 x .5 = 12x
1440 = 12x
x= 120
so the wheel needs to rotate 120 degrees, or in other words, it needs to complete a third of a rotation.
2880*0.5/12 deg = 120 deg = one third rotation only
8*360/24 = (2^6)*(3^2)*5/(2^3)*3 = (2^3)*3*5 = 120
120 degrees
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You know that it takes 2880 degrees of rotation to go 12 meters, so this is a simple ratio problem.
2880 / 12 = x / .5
2880 x .5 / 12 = x
x = 120 degrees
2880 to 12m
x to .5 m
so
2880 x .5 = 12x
1440 = 12x
x= 120
so the wheel needs to rotate 120 degrees, or in other words, it needs to complete a third of a rotation.
2880*0.5/12 deg = 120 deg = one third rotation only
8*360/24 = (2^6)*(3^2)*5/(2^3)*3 = (2^3)*3*5 = 120
120 degrees