Verified answer

a)logx (4)=1/2

(x)^1/2=4

(x)^1/2=(16)^1/2 ; x=16

b)logx (3)=1/2

(x)^1/2=3

(x)^1/2=(9)^1/2 ; x=9

c)logx (1/64)=-6

(x)^-6=1/64

1/(x)^6=1/(2)^6 ; x=2

d)logx (1/100)=-2

(x)^-2=1/100

1/(x)^2=1/(10)^2 ; x=10

e)logx (81)=-4

(x)^-4=81

1/(x)^4=(3)^4 ; x=1/3

f)logx (3)=-1

(x)^-1=3

1/(x)^1=3^1 ; x=1/3

g)log2x (4)=-2

(2x)^-2=4

1/(2x)^2=2^2 ; 2x=1/2...x=1/4

para que no te pierdas: logx(b) = a significa que toca hallar un número que elevado a la "a" dé como resultado "b", esto es: X^a = b.

entonces:

a) X^1/2 = 4 => X = 16

b) X^1/2 = 3 => X = 9

c) X^(-6) = 1/64 => X = 2

d) X^(-2) = 1/100 => X = 10

e) X^(-4) = 81 => X = 1/3

f) X^(-1) = 3 => X = 1/3

g) 2X^(-2) = 4 => 2X = 1/2 => X = 1/4