Two angles are complementary. One angle is 2° less than three times the other. Find the angles.
Let x = the number of degrees in one angle.
The other angle is almost three times bigger (3x) -- it is 2° less than 3x. So it's 3x - 2.
Since these angles are complements, they add up to 90°
x + 3x - 2 = 90
Combine like terms
4x - 2 = 90
Add 2 to both sides
4x = 92
Divide both sides by 4
x = 23
So one angle is 23°
The other is 3x - 2
3 (23) - 2
69 - 2
67°
CHECK:
Together they should add to 90°
23 + 67 = 90
ANSWER: The angles are 23° and 67°
Two angles are complementary. One angle is 2° less than three times the other. Find the angles.
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Let x be one angle.
90 - x is its complement
x = 3( 90 - x ) -2
x = 270 - 3x -2
4x = 268
x = 67
90 - x = 23
The angles have measures 67 and 23.
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Verified answer
Let x = the number of degrees in one angle.
The other angle is almost three times bigger (3x) -- it is 2° less than 3x. So it's 3x - 2.
Since these angles are complements, they add up to 90°
x + 3x - 2 = 90
Combine like terms
4x - 2 = 90
Add 2 to both sides
4x = 92
Divide both sides by 4
x = 23
So one angle is 23°
The other is 3x - 2
3 (23) - 2
69 - 2
67°
CHECK:
Together they should add to 90°
23 + 67 = 90
ANSWER: The angles are 23° and 67°
Two angles are complementary. One angle is 2° less than three times the other. Find the angles.
---------------------------------------
Let x be one angle.
90 - x is its complement
x = 3( 90 - x ) -2
x = 270 - 3x -2
4x = 268
x = 67
90 - x = 23
The angles have measures 67 and 23.