Consider y = -2^2 + 4x - 1?
Consider y = -2x^2 + 4x - 1
1. This equation is given in _
A.) Standard form
B.) Vertex form
C.) Intercept form
D.) No particular form
2. This parabola opens _
A.) Upward
B.) Right
C.) Downward
D.) Left
3. This parabola will have _
A.) A maximum
B.) A minimum
C.) Neither a maximum nor a minimum
4. The axis of symmetry is _
A.) X = 4
B.) X = -2
C.) X = 1
D.) X = -1
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1) This equation is written in the form y = ax^2 + bx + c, the standard form. A).
2) a, the x^2 coefficient, is negative -- a clear sign that this parabola opens downward. C).
3) A downward opening parabola has a vertex that is the global maximum. A).
4) The axis of symmetry is x = -b/2a.
x = -(4/2(-2)) = -(4/-4) = -(-1) = 1. C).
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