Critical Points 10x / (x^2 - 4)^2?
The original function is: f(x)
(x^2-9)
---------
(x^2-4)
f'(x) =
10x
--------------
(x^2 -4)^2
When I make f'(x) = 0 I get x=0
But I was wondering, do you use the denominator independently and get x= +or- 2?
And how would you write the answer as I have to find where the function increases and decreases
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Verified answer
That would be...
f'(x) = (10(x² - 4)² - 20x(x² - 4) * 2x)/(x² - 4)^4
= (10(x² - 4) - 40x²)/(x² - 4)³
= (-30x² - 40)/(x² - 4)³
There are no existing critical points...
Good luck!