dy/dx raiz(x)+raiz(xy)=4y^2
Veja:
√x+√xy=4y²
1/2√x+(1/2√x).√y+√x.(dy/2√y)=8ydy
1/2√x+√y/2√x+√x.dy/2√y=8ydy
1/2√x+√y/2√x=-√x.dy/2√y+8ydy
dy(8y-√x/2√y)=1/2√x+√y/2√x
Racionalizando,
dy(8y-√(xy)/2y)=√x/2x+√(xy)/2x
dy[(16y²-√(xy)]/2y=[√x+√(xy)]/2x
dy=2y[√x+√(xy)]/2x[(16y²-√(xy)]
dy=y[√x+√(xy)]/x[(16y²-√(xy)]
Que lingua é essa?
Portugues com certeza não é rsrsrsrs...
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Verified answer
Veja:
√x+√xy=4y²
1/2√x+(1/2√x).√y+√x.(dy/2√y)=8ydy
1/2√x+√y/2√x+√x.dy/2√y=8ydy
1/2√x+√y/2√x=-√x.dy/2√y+8ydy
dy(8y-√x/2√y)=1/2√x+√y/2√x
Racionalizando,
dy(8y-√(xy)/2y)=√x/2x+√(xy)/2x
dy[(16y²-√(xy)]/2y=[√x+√(xy)]/2x
dy=2y[√x+√(xy)]/2x[(16y²-√(xy)]
dy=y[√x+√(xy)]/x[(16y²-√(xy)]
Que lingua é essa?
Portugues com certeza não é rsrsrsrs...