Verified answer

You need to divide each portion of the first expression by the divisor and add them together:

(-15xy - 10x) / 5x

(-15xy / 5x) - (10x / 5x)

(-3y) - (2)

-3y - 2

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(2x^2y - 6xy^2 + 12xy) / 2xy

(2x^2y / 2xy) - (6xy^2 / 2xy) + (12xy / 2xy)

(x) - (3y) + (6)

x - 3y + 6

(-15xy - 10x)/5x start by factoring

5x(-3y - 2)/5x now, reduce

= (-3y-2)

(2x^2y - 6xy^2 + 12xy)/2xy again, factor

[2xy(x - 3y + 6)] / (2xy) and cancel

= (x - 3y + 6)

the answer to -15xy-10x/5x is -3y-2.

i dont understand the second part though is that an exponent to another power? or what?

1) (-15xy - 10x) / 5x

5x(-3y - 2) / 5x

= (-3y - 2)

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2) (2(x^2)y - 6xy^2 + 12xy) / (2xy)

[2xy(x - 3y + 6)] / (2xy)

= (x - 3y + 6)