(3x – 2)(x - 4) – (x - 4)(6 – 5x) / (4 – x)(8x – 1)
im still looking for answers seeing how every one is giving me something different. this problem seems effing imposiple..
=[3x^2 -14x+8 -(-5x^2+26x-24)]/[(4-x)(8x-1)]
= [8x^2-40x+32]/[(4-x)(8x-1)]
= 8x^2 -5x +4)/[(4-x)(8x-1)]
=(8x-1)(x-4)/[(4-x)(8x-1)]
= -1
Well, simplify it first, to (3x^2 -14x +8) + (+5x^2 + 24 - 26) / (-8x^2 +31x - 4). Then divide it.
I did some of your homework; you do the rest.
(3x-2)(x-4) = 3x^2-14x+8
(x-4)(-5x+6) = -5x^2 +26x-24
(-x+4)(8x-1) = -8x^2 -33x -4
3x^2-14x+8 - (-5x^2 +26x-24 / -8x^2 -33x -4)
thats as far as i got... sorry but hope it helps
Is this for math homework? Haha if it is nice idea;] x+4/4 is what i got
ahhh....I hated this stuff 5 years ago taking college algebra. And I forgot most of it, though here is my rough estimate if I even did it right.
Answer = 4x+32
damn what graade are u in lolz but um... i need paper and stuff and i do it different ways you can do 4x-15x(-2-5) which is equal to (-11x-7) is ur final answer!!!
use a caculater
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(3x – 2)(x - 4) – (x - 4)(6 – 5x) / (4 – x)(8x – 1)
=[3x^2 -14x+8 -(-5x^2+26x-24)]/[(4-x)(8x-1)]
= [8x^2-40x+32]/[(4-x)(8x-1)]
= 8x^2 -5x +4)/[(4-x)(8x-1)]
=(8x-1)(x-4)/[(4-x)(8x-1)]
= -1
Well, simplify it first, to (3x^2 -14x +8) + (+5x^2 + 24 - 26) / (-8x^2 +31x - 4). Then divide it.
I did some of your homework; you do the rest.
(3x-2)(x-4) = 3x^2-14x+8
(x-4)(-5x+6) = -5x^2 +26x-24
(-x+4)(8x-1) = -8x^2 -33x -4
3x^2-14x+8 - (-5x^2 +26x-24 / -8x^2 -33x -4)
thats as far as i got... sorry but hope it helps
Is this for math homework? Haha if it is nice idea;] x+4/4 is what i got
ahhh....I hated this stuff 5 years ago taking college algebra. And I forgot most of it, though here is my rough estimate if I even did it right.
Answer = 4x+32
damn what graade are u in lolz but um... i need paper and stuff and i do it different ways you can do 4x-15x(-2-5) which is equal to (-11x-7) is ur final answer!!!
use a caculater