PE => potential power PE = m * g * h, the place m => mass ( in kg) g => 9.8 m/s^2 h => height m and g being consistent, PE varies on the instant with h. So greater the h, greater the potential power. PE is on the instant proportional to h. The golf ball has the two energies. It has purely Kinetic power only earlier hitting the floor. The bouncing motives loss of power via warmth era, and inelastic nature of the collision between the ball and the floor. The ball differences course, and loses Kinetic power, and valuable components potential power because it valuable components height.
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Verified answer
It's easy.
E1 = k * x1^2 /2 = 2.0J
x2 = 3 * x1
E2 = k * x2^2 /2 = k * (3*x1)^2 /2 = 9 * k * x1^2 /2 = 9 E1 = 18.0J
Good luck!
PE => potential power PE = m * g * h, the place m => mass ( in kg) g => 9.8 m/s^2 h => height m and g being consistent, PE varies on the instant with h. So greater the h, greater the potential power. PE is on the instant proportional to h. The golf ball has the two energies. It has purely Kinetic power only earlier hitting the floor. The bouncing motives loss of power via warmth era, and inelastic nature of the collision between the ball and the floor. The ball differences course, and loses Kinetic power, and valuable components potential power because it valuable components height.