Electric Potential & Potential Energy?
A charge of 3.85 µC is held fixed at the origin. A second charge of 3.85 µC is released from rest at the position (1.15 m, 0.490 m) . If the mass of the second charge is 2.90 g, what is its speed when it moves infinitely far from the origin? _______________ m/s
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Potential energy = [(9*10^9)*{(3.85*10^-6)^2}]/{sq rt[1.15^2 + 0.490^2] = 0.5*0.00290*V^2 , where V is the required speed in m/s.
V^2 = 0.1067/{0.5*0.00290} = 73.5990 or V = 8.58 m/s