Well from Ohm's law, V=iR. You have 24V and 120mA or .120A. Using Ohm's law you can find the resistance by dividing the 24V by .120A which gives you the resistance value of 200 Ohms.
24V / .120A = 200 Ohms.
Now since you want to find the new voltage, use the information given to you about the current. Using Ohms law, you can find the voltage must be supplied to increase the current. Given the new current and knowing the resistance, use Ohm's law and you have 32V as your new voltage.
32 volts if the resistance stays constant. However it may become hotter due to the higher power dissipation which might put its resistance up, causing you to need slightly more than the 32 volts.
Answers & Comments
Verified answer
R = V/I = 24 V/120 mA = 0.2 k(ohms) = 200 ohms
V = IR = (160 mA)(200 ohms) = 32,000 mV = 32 V
So the answer would be 32 Volts. Look right? I just went over this in class so I'm not positive
Well from Ohm's law, V=iR. You have 24V and 120mA or .120A. Using Ohm's law you can find the resistance by dividing the 24V by .120A which gives you the resistance value of 200 Ohms.
24V / .120A = 200 Ohms.
Now since you want to find the new voltage, use the information given to you about the current. Using Ohms law, you can find the voltage must be supplied to increase the current. Given the new current and knowing the resistance, use Ohm's law and you have 32V as your new voltage.
V = I R
32 = .160 X 200
New voltage is 32V.
32 volts if the resistance stays constant. However it may become hotter due to the higher power dissipation which might put its resistance up, causing you to need slightly more than the 32 volts.
Both answers are correct; however, the first answer is a little confused. 30,000mA is not correct, but 32 volts is.