English major lost in a scientific world....?
Use Hess's law to calculate the enthalpy change for the following reaction:
3H2 + O3--> 3 H20
I don't even know where to begin. I've just been staring at it for a while...And there isn't a thing in my book about it.
Update:From these enthalpies of reaction:
2H2 + O2 --> 2 H2O ΔH= -483.6 kJ
3O2 --> 2 O3 ΔH= +284.6kJ
Answers & Comments
Verified answer
I can't really fully answer your question (and it's been a while since I have done hess' law) but basically in any chemical reaction bonds are broken which releases energy and bonds are made which takes energy. The enthalpy change is basically the change in energy from your reactants (3H2 and O3) and your products (3 H2O)
Hess's law states basically that the heat of a whole reaction is equivalent to the sum of it’s steps and the energy change for any chemical or physical process is independent of the pathway or number of steps required to complete the process.
If you have any info on the energy that it takes to break a H-H bond, a O-O bond in O3 and the energy it takes to make a H-O bond in water then you can work it out.
If you give me some feedback on that i'll be back later to check - need to get lunch right now.