The answer is not correct... the second factor is not (y+3)

To factor a quadratic function y = ax^2 + bx + c ... find the roots x1

and x2 and use the formula y = a(x-x1)(x-x2).

Here the roots are y = -3/4 and y = -3/2

Then it is 8(y + 3/4)(y+3/2) ... i we multiply 8 by the first factor... then it is (8y + 6)(y + 3/2)

To confirm just multiply (8y+6)(y+3/2) ... it is 8y^2 + 18y + 9 ... confirmed. OK!

Your way gives 8y^2 + 30y + 18. You want (2y + 3)(4y + 3).

(3 + 2 y) (3 + 4 y)

I get (4y + 3)(2y + 3).