Verified answer

16y² + 72y - 40 = 0

y² + 9/4y = 5/2 + (9/4)²

y² + 9/4y = 40/16 + 81/16

(y + 9/4)² = 121/16

y + 9/4 = ± 11/4

= y + 9/4 - 11/4, y = - 2/4, = y - 1/2, = 2y - 1

= y + 9/4 + 11/4, = y + 20/4, = y + 5

Answer: 8(2y - 1)(y + 5) are the factors.

16y² + 72y - 40 = 0

y² + 9/4y = 5/2 + (9/4)²

y² + 9/4y = 40/16 + 81/16

(y + 9/4)² = 121/16

y + 9/4 = ± 11/4

= y + 9/4 - 11/4, y = - 2/4, = y - 1/2, = 2y - 1

= y + 9/4 + 11/4, = y + 20/4, = y + 5

Answer: 8(2y - 1)(y + 5) are the factors.

16y^2+72y-40

= 8(2y^2 + 9y - 5)

= 8(2y-1)(y+5)

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Attn: To make it simpler, the first step is to factor the common factor 8.