factor completely 4y^(2n)-4y^n-3?
thankyou four your help
Update:assume n is a positive integer
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thankyou four your help
Update:assume n is a positive integer
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Let k = y^n; then k^2 = y^(2n), and we can rewrite the equation as
4k^2 - 4k - 3
(2k + 1)(2k - 3)
(2y^n + 1)(2y^n - 3)