Verified answer

=-15x^4-15y^4

= 15( -x^4 - y^4)

= 15 ( ((ix)^2)^2 - (y^2)^2) {a^2-b^2 form} { -x^2 = (ix)^2 , where i^2 = -1 is a complex number}

[-x^4 = ((ix)^2)^2]

= 15 ( ((ix)^2+y^2) ((ix)^2-y^2) )

= 15 ( ((ix)^2+y^2) (ix+y) (ix-y) )

= 15 ( (y^2-x^2) (ix+y) (ix-y) )..............{ i^2=-1--> (ix)^2 = -x^2 --> (ix)^2+y^2 --> y^2-x^2}

= 15 ( y+x)(y-x)(ix+y)(ix-y)

These are the factors...

-15 ( x^4 +y^4) ANSWER

15x^4 - 15y^4

= 15(x^4 - y^4)

= 15(x^2 - y^2) (x^2 + y^2)

= 15(x - y)(x + y) (x^2 + y^2)

15x^4 - 15y^4

= 15(x^4 - y^4)

= 15(x^2 - y^2)(x^2 + y^2)

= 15(x - y)(x + y)(x^2 + y^2)

Edit: Re: Negative? Again, your statement is very confusing, if that really is a negative in front please write it as:

Factorize completely: -15x^4-15y^4 , then it will be:

-15x^4-15y^4

= -15(x^4 + y^4)

15(-x^4-y^4)

-15(x^4+y^4)

x(x^2-7x+12) yet differently is to set this finished polynomial function to 0..or EQUALS to 0 a million) 0=x^3-7x^2+12x 2) what's the selection once you plug into the equation and get a nil? the respond is whilst x=3 (consequently) . So (x-3) is ONE ingredient via fact whilst x-3=0, x=3 (once you progression the three over) (i'm unsure in case you instructor instructed u this yet. i'm in Gr.12 and we only lined that final month) 3) use guy made branch (one way of dividing polynomials) for this reason your answer must be: (x-3)(x^2 - 4x).