This is a bit of a trick question. At first glance, it looks like it may be an oxidation-reduction question, but it's not! Check the oxidation state of Fe. It's 3+ on both sides of the arrow. That means that this is simply a double displacement reaction. Think of water as HOH. You're swapping NO3- for OH-
You just need to balance atoms on both sides of the arrow. The easiest thing to start with is OH- (thinking of water as H+ and OH-). There are 3 OH-'s on the right side which must have come from the water, so there needs to be a 3 placed in front of the water on the left side of the arrow. Then look at NO3-. There were 3 on the left side of the arrow, so there must be 3 on the right side. Place a 3 in front of HNO3. Now check to see that all atoms balance. You should end up with:
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Fe(NO3)3 + 3H2O ----> Fe(OH)3 + 3HNO3
Fe No3 3 H2o
This is a bit of a trick question. At first glance, it looks like it may be an oxidation-reduction question, but it's not! Check the oxidation state of Fe. It's 3+ on both sides of the arrow. That means that this is simply a double displacement reaction. Think of water as HOH. You're swapping NO3- for OH-
You just need to balance atoms on both sides of the arrow. The easiest thing to start with is OH- (thinking of water as H+ and OH-). There are 3 OH-'s on the right side which must have come from the water, so there needs to be a 3 placed in front of the water on the left side of the arrow. Then look at NO3-. There were 3 on the left side of the arrow, so there must be 3 on the right side. Place a 3 in front of HNO3. Now check to see that all atoms balance. You should end up with:
Fe(NO3)3 + 3 H2O ---> Fe(OH)3 + 3 HNO3
Fe(NO3)3 + 3H20 ---> Fe(OH)3 + 3H(NO3)
im pretty sure thats it?
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Cu(s) + 4HNO3 (aq)--> Cu(NO3)2(aq) + 2H2O(l) +2NO2(g)
No the reason it s a trick question is because HNO3 is a strong acid. This reaction is not energetically favorable and will not occur.
hno3 _fe