General Chemistry 2 Question?
Carbon Monoxide(0.40mol) and water(0.4 mol) are placed in a 2.0 vessel and are allowed to reach equilibirum at 100 degrees celsius.where the equilibrium constant k= 0.58. Calculate the equilibrium concentrations of the 4 gases:
Equation: CO(g)+H2O(g)=> CO2(g)+H2(g) Kc=0.58@100degrees Celsius
Using the ICE might help but I have trouble with that alot.
Thanks!
Answers & Comments
Verified answer
CO + H2O --> CO2 + H2
Kc = 0.58
CO.....H2O.....CO2.....H2
0.4......0.4.......0..........0
-x.........-x.......+x........+x
0.4-x..0.4-x......x..........x
Kc = [CO2[H2] / [CO][H2O]
0.58 = x^2 / (0.4-x)^2
0.58 = x^2 / x^2 - 0.8x + 0.16
0.58x^2 - 0.464x + 0.093 = x^2
0.42x^2 + 0.46x - 0.093 = 0
x = 0.174
[CO] = [H2O] = 0.4 - x = 0.4 - 0.178 = 0.226M
[CO2] = [H2] = x = 0.178M