At 23°C, Kp = 0.075 for the equilibrium:
NH4HS (s) ↔ NH3 (g) + H2S (g)
A sample of solid NH4HS is placed in a closed vessel and allowed to equilibrate. Calculate the equilibrium partial pressure (atm) of ammonia, assuming that some solid NH4HS remains.
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Verified answer
NH4HS(s) <==> NH3(g) + H2S(g) ......... Kp = 0.075
.........................? atm
Kp = P(NH3) x P(H2S)
0.075 = x²
x = 0.27
P(NH3) = 0.27 atm ...... to two significant digits