General Chemistry Question?
Calculate the molarity of the following aqueous solutions: (a) 62.0 g K2C2O4 in 747 mL of solution; (b) 126 g C6H12)6 in 350 mL of solution; (c) 26.0 g BaCl2 in 0.825L of solution.
More Questions From This User See All
Answers & Comments
Verified answer
molarity is just concentration in mol/L
You need to first calculate the molar mass, convert to the number of moles then divide by the volume they give you.
a) K2C2O4 = 166.2g/mol --> 62/166.2 = 0.373mol
0.373mol/0.747L = 0.5mol/L = 0.5M
b) I'm guessing you meant C6H12O6
C6H2O6 = 180g/mol --> 126/180 = 0.7mol
0.7/0.35 = 2M
c) BaCL2 = 208.23g/mol --> 26/208.23 = 0.12486mol
0.12486/0.825 = 0.15M