I really need help solving for a1 in this geometric sequence:
an = 24, r = 2/3, n = 4
In addition, I also need help with this sequence as well:
Sn = 1022, r = 2, n = 9
Showing your steps would be a big help. Thank you very much.
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Verified answer
a1 = 81
for an = 24, r = 2/3, n = 4
an = a1(r)^(n-1) [given formula]
substitute in our known variables
24 = a1 (2/3)³
divide both sides by (2/3)³
24 / (2/3)³ = a1
reverse the two sides of the equality
a1 = 24/ (2/3)³
convert the fraction
a1 = 24 / (8/27)
multiply the numerator and the denominator on the right by 27
a1= 24(27)/8
do the arithmetic
a1 = 81
[Cheater method if you forgot the formula: You could also get this by working backward from a4 = 24 (an = 24 where n=4).
a3 = (3/2) a4 because a4 = (2/3) a3
[that's what r = 2/3 means: an+1 = (2/3)an]
<note: an+1 means 'a' with the subscript n+1, not 1 more than an>
a3 = (3/2)24
a3 = 36
a2 = (3/2) a3 also because a3 = (2/3) a3
a2 = (3/2) 36
a2 = 54
a1 = (3/2) a2
a1 = (3/2) 54
a1 = 81
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a1 = 2
for Sn = 1022, r = 2, n = 9
Sn = a1(1-r^n) / (1-r) [given formula]
substitute givens for variables
1022 = a1(1-2^9)/1-2
expand 2^9 = 2^4*2^4*2 = 16*16*2 = 256*2 = 512
1022 = a1 (1-512) / 1-2
simplify the numerator and denominator
1022 = a1 (-511) / -1
minus signs disappear an dthe denominator of 1 disappears
1022 = a1 (511)
divide both sides by 511
1022 / 511 = a1
simplify fraction
2 = a1
reverse
a1 = 2
check: series begins with a1 = 2, it increases by a factor of 2 (thats what r = 2 means) for nine factors:
2 + 4 + 8 + 16 + 32 + 64 + 128 + 256 + 512 =
6 + 24 + 96 + 384 + 512 =
30 + 480 + 512 =
510 + 512 =
1022