Verified answer

If the generator produces 30 volts rms and it had little or no internal resistance, the

current through the 30-ohm load resistor would be 1 ampere, by Ohm's Law.

If the total current in the circuit is 0.5 ampere, then the total circuit resistance is

30 divided by 0.5, or 60 ohms. The external load resistance is 30 ohms, so the

internal resistance of the generator is 60 - 30, or 30 ohms.

The total power delivered is equal to the product of the voltage and current, so it is

30 times 0.5, or 15 watts. Since the resistance of the generator and load resistor

are equal (30Ω each) then the power delivered to the load and power dissipated in

the generator are also equal, being 7.5 watts each. (half in the generator and half

delivered to the load resistor)