Given: x^(2) + y^(2) - 2x - 4y - 4 = 0?
Which of the following is correct?
a. This is a circle with center at (1, 2) and radius 3.
b. This is a circle with center at (-1, 2) and radius 3.
c. This is a circle with center at (1, -2) and radius 3.
d. This is a circle with center at (-1, -2) and radius 3.
e. None of these is correct
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answer a is correct because if you put the equation in circle form, you get:
(x-1)^2 + (y-2)^2 = 3^2
hope that helps...
x^(2) + y^(2) - 2x - 4y - 4 = 0
( x^(2) - 2x +1) + ( y^(2) - 4y + 4 ) = 9
( x - 1)^(2) + ( y - 2 ) ^(2) = 3^(2)
So it is a. This is a circle with center at (1, 2) and radius 3.
Answer will be 'e-None of these,' try replcing values of x, y with center coordinates.
b.