Verified answer

10+e^(5-x) = 33 <== Is this what you want to solve?

e^(5-x) = 23

Change it to ln form,

5-x = ln23

x = 5-ln23

10+e^5-x=33

e ^ (5 - x) = 23

5 - x = Ln23

x = 5 - Ln23 ans

10+e^5-x=33

x = 23-e^5

e^(5-x)=23

take ln on both side

5-x=ln(23)

x=5-ln(23)