Help on PV=nRT Ideal Gas Law Chemistry problem?
Here is the info:
A 1.3- container of liquid nitrogen is kept in a closet measuring 1.1 by 1.1 by 2.0 . Assuming that the container is completely full, that the temperature is 27.2, and that the atmospheric pressure is 1.1 atm, calculate the percent (by volume) of air that would be displaced if all of the liquid nitrogen evaporated. (Liquid nitrogen has a density of 0.807 .)
Please explain and show your work so I can understand it! Thanks so much for your help!!
Update:Sorry! It is 1.3 L. Please leave an answer if you figure it out. Thanks!!
Update 3:And the closet dimensions are 1.1 m, 1.1 m, and 2.0 m.
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What are the units on the 1.3- (?) and on the closet dimensions?
Firstly, the volume of air displaced would be equal to the volume of N2(g) formed. So the percent (by volume) of air displaced will be:
% displaced = [V(displaced) / V(total)](100%) ... or:
% displaced = [V(N2(g)) / V(closet)](100%)
You can calculate V(closet) easily because you're given the three dimensions (V = (l)(w)(h)). You will want to convert this volume to liters, since that's the unit of volume in the ideal gas equation. There are 1000L in 1m^3.
Since I don't know what the units are that you're given for the container of liquid N2, I can't help you with the rest of the problem [solving for V(N2(g))], other than to say this: you will have to do some unit conversion in order to get a number that you can use in the ideal gas equation.
PV = nRT
V = nRT / P
You have everything here except for n, but you are given the density of liquid N2 (0.807g/mL) and if you know the volume of the container of liquid N2 you can calculate mass of N2. Then you can substitute the molar mass equation into the gas law:
n = m/mm ... m = mass (g), mm = molar mass (g/mol)
V = nRT / P
V = (m/mm)(RT / P)
V = mRT / mmP
T temperature to be measured on kelvin scale.. i.e. 19+273 ok and no of moles.. weight divided by skill of molecular weight fee of R 2 b chosen accordin to the gadgets used for pressur en quantity.. if u use atm-l then the fee of R is 0.0821 if u use pascal-m^3 fee is 8.314 and for calculation of warmth or power in energy, fee of R shud be approximated to 2