Verified answer

If the engine does 38 J of work and wastes another 25 J, then it is necessary to input

(38+25) J of energy into it to get the useful output of 38 J. Efficiency is usually stated as a

percentage of what part of the energy put into a machine is output as useful work. So

Eff = [38J/(38+25)J]*100%

I will let you do the arithmetic of finding the number for the percentage.

ok, specially instances to get sturdy at those issues, you basically gotta toss a great variety of stuff up interior the air! anyhow, section A: The products acceleration will at last substitute into gravity, as no different forces are performing on it. Numerically: -9.80 one m/s^2 B: speed is substitute of place over substitute of time. simply by fact there is not any rigidity in this element, its impossible to alter speed quickly, so the element will provide up, after which come down, or 0 m/s C: i became incorrect approximately section C. wonderful answer: you have v1 = 5 m/s, v2 = 0 m/s and place is 10 m. the fee is substitute of distance over a time-physique. the time-physique is x / dS (substitute of speed) or 10 / 5 = 2 seconds.